How much bituminous coal needs to be burned to get 270 kJ of heat?

univerkov | November 27, 2020 | education

Given:
Q = 270kJ
Find: m-?
Decision:
Q = qm
qcoal = 2.7 × 10 ^ 7J / kg
Q = 270000J
m = Q / q
m = 270000J / 27000000J / kg = 0.01kg
Answer: 0.01 kg

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