How much bromoethane can be obtained from 4.48 liters. methane?

univerkov | September 3, 2021 | education

Methane can produce bromomethane, not bromoethane.
CH4 + Br2 = CH3Br + HBr
Let’s find the amount of methane: n = V / Vm, where Vm = 22.4 l / mol – molar volume, constant for all gases under normal conditions. n (CH4) = 4.48 L / 22.4 L / mol = 0.2 mol.
According to the reaction from 1 mol of methane, we get 1 mol of bromomethane, which means n (CH4) = n (CH3Br) = 0.2 mol.
By mass, this will be: m (CH3Br) = n * M = 0.2 mol * (12 + 3 + 80) g / mol = 19 g.
Answer: we get 0.2 mol or 19 g of bromomethane.

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