How much by weight of acetic acid can be obtained from 112 g of ethanal by performing the “silver mirror” reaction.

| September 9, 2021 | education

First, we write down the equation of reactions, that is, the reaction of the silver mirror.

CH3COH + Ag2O —-> CH3COOH + 2Ag.
This reaction takes place under the influence of NH4OH.
Find the molar mass of ethanal. We write down the solution.
M (CH3COH) = 44g / mol.
Next, we find the amount of ethanal substance according to the following formula.
n = m / M.
Where n is the amount of substance.
m is the mass of the substance.
M is the molar mass of the substance.
n (CH3COH) = 112 g / 44g / mol = 2.5 mol.
We make up the proportion.
2.5 mol СН3СОН – х mol СН3СООН.
1 mol СН3СОН – 1 mol СН3СООН.
Find the amount of CH3COOH substance.
x = 2.5 × 1 ÷ 1 = 2.5 mol.
n (CH3COOH) = 2.5 mol.
We find the mass of CH3COOH.
m (CH3COOH) = n × M = 2.5 × 60 = 150g.
Answer: the mass of acetic acid is 150 grams.



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