How much calcium is in 250 g calcium carbonate containing 12% impurities?

univerkov | April 30, 2021 | education

1. Let’s calculate the mass of pure calcium carbonate:
m (CaCO3) = m (with impurities) – m (impurities) = 250- (250 * 0.12) = 220 g
2. Let’s make the proportion:
Mr (CaCO3) – 220 g
Ar (Ca) – X
Molecular weight of calcium carbonate: Mr (CaCO3) = 40 + 12 + 16 * 3 = 100
Atomic weight of calcium Ar (Ca) = 40
100-220
40-X
X = 220 * 40/100 = 88g

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