How much calcium oxide will be obtained when firing 500 g of limestone containing 70% caco3?

The limestone roasting reaction is described by the following equation:

CaCO3 = CaO + CO2 ↑;

The decomposition of 1 mol of limestone synthesizes 1 mol of calcium oxide and 1 mol of carbon monoxide.

Find the chemical amount of calcium carbonate. To do this, divide its weight by its molar mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol; N CaCO3 = 500 x 0.7 / 100 = 3.5 mol;

Determine the weight of 3.5 mol of calcium oxide.

For this purpose, we multiply the amount of the substance by its molar weight.

M CaO = 40 + 16 = 56 grams / mol; m CaO = 3.5 x 56 = 196 grams;