How much calcium phosphate is required to produce 5 tons of phosphorus?

m (P) = 5 t.
Determine the mass of calcium phosphate. We write down the solution.
First, we write down the equation of reactions.
2Ca3 (PO4) 2 + 6SiO2 + 10C = 6CaSiO3 + P4 + 10СО.
Find the molar mass of calcium phosphate.
M (Ca3 (PO4) 2) = 3 * 40 + 31 * 2 + 16 * 8 = 120 + 62 + 128 = 310 g / mol.
Find the molar mass of phosphorus.
M (P) = 31 g / mol.
Next, we find the mass of calcium phosphate using the reaction equation.
5 t = 5,000,000 g.
X g Ca3 (PO4) 2 – 5,000,000 g R.
2 * 310 g / mol Ca3 (PO4) 2 – 31 g / mol R.
X = 2 * 310 * 5,000,000: 31 = 100,000,000 g = 100 t Ca3 (PO4) 2.
Answer: m (Ca3 (PO4) 2) = 100 t.