How much carbon dioxide can be obtained from 12 kg of natural limestone containing 80% calcium carbonate?

The limestone decomposition reaction is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

The decomposition of 1 mol of limestone synthesizes 1 mol of gaseous carbon dioxide.

Let’s calculate the available chemical amount of calcium carbonate substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 12,000 x 0.8 / 100 = 96 mol;

During the reaction, the same amount of carbon dioxide will be synthesized.

Let’s calculate its volume.

To do this, we multiply the amount of substance and the standard volume of 1 mole of gaseous substance.

1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 96 x 22.4 = 2 150.4 liters = 2.15 m3;