How much carbon dioxide (carbon monoxide 4) will be released when 10 mol of sodium carbonate

How much carbon dioxide (carbon monoxide 4) will be released when 10 mol of sodium carbonate interacts with hydrochloric acid.

Let’s compose the reaction equation, find the quantitative relationships of substances.

Na2CO3 + 2HCl = 2 NaCl + CO2 ↑ + H2O.

According to the reaction equation, 1 mol of sodium carbonate accounts for 1 mol of carbon dioxide. Substances are in quantitative ratios 1: 1.

The amount of sodium carbonate substance and carbon dioxide will be equal.

n (Na2CO3) = n (CO2) = 10 mol.

Let’s find the volume of carbon dioxide.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 10 mol × 22.4 L / mol = 224 L.

Answer: 224 l.