How much carbon dioxide is formed by the interaction of 250 kg. potassium carbonate with nitric acid?

Given:
m (K2CO3) = 250 kg = 250,000 g

Find:
V (CO2) -?

Solution:
1) Write the reaction equation:
K2CO3 + 2HNO3 => 2KNO3 + CO2 ↑ + H2O;
2) Calculate the molar mass of K2CO3:
M (K2CO3) = Mr (K2CO3) = Ar (K) * 2 + Ar (C) + Ar (O) * 3 = 39 * 2 + 12 + 16 * 3 = 138 g / mol;
3) Calculate the amount of substance K2CO3:
n (K2CO3) = m (K2CO3) / M (K2CO3) = 250000/138 = 1811.6 mol;
4) Determine the amount of substance CO2:
n (CO2) = n (K2CO3) = 1811.6 mol;
5) Calculate the volume of CO2:
V (CO2) = n (CO2) * Vm = 1811.6 * 22.4 = 40579.84 liters.

Answer: The volume of CO2 is 40579.84 liters.