How much carbon dioxide is formed by volume when 10 liters of benzene are burned?

Let’s execute the solution:
1. Let’s compose an equation, arrange the coefficients:
2С6Н6 + 15О2 = 12СО2 + 6Н2О – the reaction of benzene combustion is accompanied by the release of carbon dioxide and water;
2. Let’s calculate the amount of moles of benzene, carbon monoxide (4):
1 mol of gas at normal level – 22.4 liters;
X mol (C6H6) – 10 liters. hence, X mol (C6H6) = 1 * 10 / 22.4 = 0.446 mol;
0.446 mol (C6H6) – X mol (CO2);
– 2 mol                     – 12 mol from here, X mol (CO2) = 0.446 * 12/2 = 2.676 mol.
3. Find the volume of CO2:
V (CO2) = 2.676 * 22.4 = 59.94 liters.
Answer: in the process of the combustion reaction, carbon dioxide with a volume of 59.94 liters was released.