How much carbon dioxide is generated by the decomposition of 60g calcium carbonate?

The decomposition reaction of calcium carbonate is described by the following chemical equation:

Na2CO3 = Na2O + CO2;

One mole of calcium carbonate produces one mole of carbon dioxide.

Let’s determine the molar amount of a substance in 60 grams of calcium carbonate.

To do this, first determine its molar mass:

M Na2CO3 = 23 x 2 + 12 + 16 x 3 = 106 grams / mol;

The amount of substance will be:

N Na2CO3 = 60/106 = 0.566 mol;

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let us determine the volume of 0.566 mol of carbon dioxide:

V Na2CO3 = 0.566 x 22.4 = 12.6784 liters;