How much carbon dioxide is generated when 6 grams of propanol is burned?

The oxidation reaction of propanol is described by the following chemical reaction equation.

C3H7OH + 9/2 O2 = 3CO2 + 4H2O;

According to the coefficients of this equation, 4.5 oxygen molecules are required for the oxidation of 1 alcohol molecule. This synthesizes 3 molecules of carbon dioxide.

Let’s calculate the amount of ethanol available.

To do this, we divide the mass of the substance by its molar weight.

M C3H7OH = 12 x 3 + 8 + 16 = 60 grams / mol;

N C3H7OH = 6/60 = 0.1 mol;

The amount of oxygen will be.

N CO2 = 0.1 x 3 = 0.3 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V CO2 = 0.3 x 22.4 = 6.72 liters;