How much carbon dioxide is produced by the thermal decomposition of 3 mol of potassium bicarbonate?

univerkov | February 16, 2021 | education

Given:
n (KHCO3) = 3 mol

To find:
V (CO2) -?

1) 2KHCO3 => K2CO3 + CO2 ↑ + H2O;
2) n (CO2) = n (KHCO3) / 2 = 3/2 = 1.5 mol;
3) V (CO2) = n * Vm = 1.5 * 22.4 = 33.6 liters.

Answer: The CO2 volume is 33.6 liters.

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