How much carbon dioxide is produced when 12.1 g of butanal is burned?

The oxidation reaction of butanal is described by the following chemical reaction equation.

C4H8O + 11 / 2O2 = 4CO2 + 4H2O;

According to the coefficients of this equation, 5.5 oxygen molecules are required to oxidize 1 butanal molecule. In this case, 4 molecules of carbon dioxide are synthesized.

Let’s calculate the available amount of butanal.

To do this, divide the weight of the available gas by the weight of 1 mole of this gas.

М С4Н8О = 12 x 4 + 8 + 16 = 72 grams / mol;

N C4H8O = 12.1 / 72 = 0.168 mol;

The amount of carbon dioxide will be.

N CO2 = 0.168 x 4 = 0.672 mol;

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V CO2 = 0.672 x 22.4 = 15.053 liters;