How much carbon dioxide is produced when 4 liters of butane are burned?
September 27, 2021 | education
| The butane oxidation reaction is described by the following chemical reaction equation.
2C4H10 + 13O2 = 8CO2 + 10H2O;
According to the coefficients of this equation, 13 oxygen molecules are required to oxidize 2 butane molecules. In this case, 8 molecules of carbon dioxide are synthesized.
Let’s calculate the amount of butane available.
To do this, we divide the available gas volume by the volume of 1 mole of ideal gas under normal conditions.
N C4H10 = 4 / 22.4 = 0.179 mol;
The amount of carbon dioxide will be.
N CO2 = 4 x N C4H10 = 0.179 x 4 = 0.716 mol;
Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.
Its volume will be: V CO2 = 0.716 x 22.4 = 16.038 liters;
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