How much carbon dioxide is produced when 50 liters of natural gas containing 95% methane are burned?

1. Let’s write down the reaction equation:

CH4 + 2O2 = CO2 + 2H2O.

2. Find the amount of methane (Vm – molar volume, constant equal to 22.4 l / mol):

V (CH4) = (V (mixture) * ω (CH4)) / 100% = 50 l * 95% / 100% = 47.5 l.

n (CH4) = V (CH4) / Vm = 47.5 L / 22.4 L / mol = 2.12 mol.

3. Using the reaction equation, we find the amount and then the volume of carbon dioxide:

n (CO2) = n (CH4) = 2.12 mol.

V (CO2) = n (CO2) * Vm = 2.12 mol * 22.4 l / mol = 47.5 l.

Answer: V (CO2) = 47.5 liters.