How much carbon dioxide is produced when 84 g of carbon monoxide is burned in 26.88 liters of oxygen?

Given:
m (CO) = 84 g
V (O2) = 26.88 L

To find:
V (CO2) -?

1) 2CO + O2 => 2CO2;
2) n (CO) = m / M = 84/28 = 3 mol;
3) n (O2) = V / Vm = 26.88 / 22.4 = 1.2 mol;
4) V (CO2) = V (O2) * 2 = 26.88 * 2 = 53.76 l.

Answer: The CO2 volume is 53.76 liters.



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