How much carbon dioxide is released during the combustion of 2L of propane?

univerkov | September 21, 2021 | education

1. Let’s write down the reaction equation:

C3H8 + 5O2 = 3CO2 + 4H2O.

2. Find the amount of propane (Vm – molar volume, constant equal to 22.4 l / mol):

n (C3H8) = V (C3H8) / Vm = 2 L / 22.4 L / mol = 0.089 mol.

3. Using the reaction equation, we find the amount and then the volume of carbon dioxide:

3n (CO2) = n (C3H8).

n (CO2) = n (C3H8) / 3 = 0.089 mol / 3 = 0.03 mol.

V (CO2) = n (CO2) * Vm = 0.03 mol * 22.4 L / mol = 0.67 L.

Answer: V (CO2) = 0.67 l.

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