How much carbon dioxide is released when burning 300 g of propyne?

univerkov | December 3, 2020 | education

C3H4 + 4O2 = 3CO2 + 2H2O
n (C3H4) = m \ M = 300 \ 40 = 7.5 mol
n (CO2) at ur-th p-i = 7.5 * 3 = 22.5 mol
V (CO2) = n * Vm = 22.5 * 22.4 = 504 l
Answer: 504 l

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