1. Let’s write down the reaction equation:
Ca (OH) 2 + CO2 = CaCO3 + H2O.
2. Find the amount of calcium hydroxide:
m (Ca (OH) 2) = (m (solution) * ω (Ca (OH) 2)) / 100% = 148 g * 2% / 100% = 2.96 g.
n (Ca (OH) 2) = m (Ca (OH) 2) / M (Ca (OH) 2) = 2.96 g / 74 g / mol = 0.04 mol.
3. According to the reaction equation, we find the amount, and then the volume of carbon dioxide (Vm – molar volume, constant equal to 22.4 l / mol):
n (CO2) = n (Ca (OH) 2) = 0.04 mol.
V (CO2) = n (CO2) * Vm = 0.04 mol * 22.4 l / mol = 0.896 l.
Answer: V (CO2) = 0.896 l.
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