How much carbon dioxide will be released if 10.6 g of sodium carbonate is treated with hydrochloric acid?

univerkov | July 1, 2021 | education

Given:
m (Na2CO3) = 10.6 g

To find:
V (CO2) -?

1) Na2CO3 + 2HCl => 2NaCl + CO2 ↑ + H2O;
2) n (Na2CO3) = m / M = 10.6 / 106 = 0.1 mol;
3) n (CO2) = n (Na2CO3) = 0.1 mol;
4) V (CO2) = n * Vm = 0.1 * 22.4 = 2.24 l.

Answer: The CO2 volume is 13.4 liters.

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