How much carbon dioxide will be released when 18 g of acetic acid reacts with sodium bicarbonate?

1. Let’s write down the reaction equation:
Na2CO3 + 2CH3COOH = 2CH3COONa + CO2 + H2O.

2. Find the amount of acetic acid:

n (CH3COOH) = m (CH3COOH) / M (CH3COOH) = 18 g / 60 g / mol = 0.3 mol.

3. According to the reaction equation, we find the amount, and then the volume of carbon dioxide (Vm – molar volume, constant equal to 22.4 l / mol):

n (CO2) = 2n (CH3COOH) = 2 * 0.3 mol = 0.6 mol.

V (CO2) = n (CO2) * Vm = 0.6 mol * 22.4 l / mol = 13.44 l.

Answer: V (CO2) = 13.44 liters.



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