How much carbon dioxide will be released when 5 liters of ethane are burned?

We carry out the solution:
1. We compose the equation according to the condition of the problem:
V = 5 liters. X l. -?
2С2Н6 + 7О2 = 4СО2 + 6Н2О + Q – combustion of ethane, carbon dioxide and water are released;
2. Proportions:
1 mol of gas at normal level – 22.4 liters;
X mol (C2H6) – 5 liters. hence, X mol (C2H6) = 1 * 5 / 22.4 = 0.223 mol;
0.223 mol (C2H6) – X mol (CO2);
-2 mol – 4 mol from here, X mol (CO2) = 0.213 * 4/2 = 0.426 mol.
3. Find the volume of CO2:
V (CO2) = 0.426 * 22.4 = 9.54 l.
Answer: carbon monoxide with a volume of 9.54 liters was released.