How much carbon dioxide will be released when 60 kg of coal is burned?

univerkov | December 10, 2020 | education

С + О2 -> СО2 m (C) = 60 kg = 60,000 g n (C): n (CO2) = 1: 1 n (C) = m (C) / M (C) = 60,000 / 12 = 5000 mol = = n (CO2) V (CO2) = n (CO2) * Vm = 5000 * 22.4 = 112000 l

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