How much carbon dioxide will be released when sodium carbonate interacts with 30 g of 20% hydrochloric acid?

1. Let’s write down the reaction equation:

Na2CO3 + 2HCl = 2NaCl + CO2 + H2O.

2. Find the amount of hydrochloric acid:

m (HCl) = (m (solution) * ω (HCl)) / 100% = 30 g * 20% / 100% = 6 g.

n (HCl) = m (HCl) / M (HCl) = 6 g / 35.5 g / mol = 0.16 mol.

3. According to the reaction equation, we find the amount of carbon dioxide, and then its volume (Vm – molar volume, constant equal to 22.4 l / mol):

n (CO2) = 2n (HCl) = 2 * 0.16 mol = 0.33 mol.

V (CO2) = n (CO2) * Vm = 0.33 mol * 22.4 l / mol = 7.36 l.

Answer: V (CO2) = 7.36 liters.