How much carbon monoxide 4 is produced when 784 liters of ethylene are burned?

Let’s compose the reaction equation for the combustion of ethylene (ethene):
C2H4 + 3O2 = 2CO2 + 2H2O;

The volume of one mole of gas is 22.4 liters. Let’s find the amount of substance in ethylene:
784 / 22.4 = 35 mol;

Before carbon monoxide there is a 2 times higher coefficient than before ethylene. This means that the amount of substance in carbon dioxide is 70 mol. Let’s find the volume of carbon dioxide:
70 * 22.4 = 1568 liters;

Answer: The volume of carbon dioxide is 1568 liters.