How much carbon monoxide (4) is released when a solution containing 2.3 g of formic acid

How much carbon monoxide (4) is released when a solution containing 2.3 g of formic acid interacts with an excess of calcium carbonate.

1. The interaction of formic acid with calcium carbonate describes the reactions:
2HCOOH + CaCO3 = (HCOO) 2Ca + H2O + CO2 ↑;
2. Calculate the chemical amount of formic acid:
n (HCOOH) = m (HCOOH): M (HCOOH);
M (HCOOH) = 1 + 12 + 32 + 1 = 46 g / mol;
n (HCOOH) = 2.3: 46 = 0.05 mol;
3. Let’s set the amount of released carbon dioxide:
n (CO2) = n (HCOOH): 2 = 0.05: 2 = 0.025 mol;
4. Let’s calculate the volume of carbon dioxide:
V (CO2) = n (CO2) * Vm = 0.025 * 22.4 = 0.56 l.
Answer: 0.56 l.