How much carbon monoxide (IV) will be required to obtain calcium bicarbonate from 7.4 g of calcium hydroxide?

The reaction for the synthesis of calcium bicarbonate takes place in two stages.

Ca (OH) 2 + CO2 = CaCO3 + H2O;

CaCO3 + H2O + CO2 = Ca (HCO3) 2;

For the synthesis of 1 mol of calcium bicarbonate, 1 mol of calcium hydroxide and 2 mol of carbon dioxide are required.

Let’s calculate the amount of calcium hydroxide available.

M Ca (OH) 2 = 40 + 16 x 2 + 1 x 2 = 74 grams / mol;

N Ca (OH) 2 = 7.4 / 74 = 0.1 mol;

Therefore, 0.2 mol of carbon dioxide will be required. Let’s calculate its volume. To do this, multiply the amount of the substance and the standard volume of 1 mole of the gaseous substance. 1 mole of ideal gas fills a volume of 22.4 liters under normal conditions.

V CO2 = 0.2 x 22.4 = 4.48 liters;