How much CH4 methane needs to be burned to obtain 2400 g of CO2?

The methane oxidation reaction is described by the following chemical reaction equation.

CH4 + 2O2 = CO2 + 2H2O;

According to the coefficients of this equation, the oxidation of 1 methane molecule requires 2 oxygen molecules. This synthesizes 1 molecule of carbon dioxide.

Let’s calculate the amount of substance contained in 2400 grams of carbon dioxide.

M CO2 = 12 + 16 x 2 = 44 grams / mol;

N CO2 = 2400/44 = 54.545 mol;

The same amount of methane will be required.

Let’s calculate the gas volume. To do this, multiply the amount of substance by the volume of 1 mole of gas.

Its volume will be: V CH4 = 54.545 x 22.4 = 1 221.81 liters;