How much chlorine is required to obtain 245 g of berthollet’s salt?

In order to solve the problem, you must:

1) Write the equation of the reaction and inscribe above the substances the data that are provided according to the conditions of the problem:

3Cl2 + 6KOH → KClO3 + 5KCl + 3H2O

2) Since, according to the condition of the problem, we are given the mass of berthollet’s salt, then we need to find the amount of matter (KClO3):

To find it, also using the periodic table, we find the molar mass of berthollet salt:

M (KClO3) = 39 + 35.5 + 16 * 3 = 39 + 35.5 + 48 = 122.5 g / mol

It turns out:

ν (KClO3) = m / M = 245 / 122.5 g / mol = 2 mol

3) According to the reaction equation, we see that the amount of berthollet’s salt substance is three times less than the amount of chlorine substance:

ν (CO2) = ν (CH4) = 3: 1 = 3 * 2 mol = 6 mol

4) Find the volume of chlorine required to obtain 245 g of berthollet’s salt:

ν (Cl2) = ν * Vm = 6 mol * 22.4 l / mol = 134.4 l.

Answer: 134.4 liters is the volume of chlorine that will be required to obtain 245 g of berthollet’s salt.