How much CO is needed to reduce 560 kg of iron from Fe2O3?

univerkov | September 20, 2021 | education

Solution:
Fe2O3 + 3CO = 3CO2 + 2Fe
1) v (Fe) = m / M = 560000/56 = 10000 mol
2) v (CO) = 1.5 * v (Fe) = 15000 mol
3) m (CO) = v * M = 15000 * 28 = 420 kilograms or
3) V (CO) = v * Vm = 15000 * 22.4 = 336000 liters
Answer: 420 kilograms or 336,000 liters

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