How much CO2 can be obtained by thermal decomposition 200g. CaCO3 containing 20% impurities?

The decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

From one mole of calcium carbonate, one mole of carbon dioxide is formed.

Determine the amount of calcium carbonate substance involved in the reaction.

The mass of the pure substance will be:

m CaCO3 = 200 x 0.8 = 160 grams;

Let’s find the amount of substance in this mass.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of the substance will be.

N CaCO3 = 160/100 = 1.6 mol;

The same amount of carbon dioxide will be produced.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide.

V CO2 = 1.6 x 22.4 = 35.84 liters;