How much CO2 can react with Ca (OH) 2 if 50 g of residue falls out?

Given:
m (sediment) = 50 g
To find:
V (CO2) =?
Solution:
1) Let’s compose the equation of the chemical reaction, let the volume of carbon dioxide be x l.
СO2 + Ca (OH) 2 = CaCO3 + H2O
2) Find the molecular weight of the precipitate, that is, CaCO3.
M (CaCO3) = 40 + 12 + (16 x 3) = 100 g / mol
3) The molar volume of CO2 = 22.4 l / mol.
4) x L: 22.4 L / mol = 50 x 100 g / mol
x = (22.4 x 50): 100 = 11.2 l
Answer: V (CO2) = 11.2 liters.