How much CO2 will be released when 365 g. 20% HCL interacts with calcium carbanate?

univerkov | March 19, 2021 | education

2HCl + CaCO3 = CO2 + H2O + CaCl2.
1. Find the mass of the solute of hydrochloric acid in its solution. To do this, multiply the mass of the solution by the mass fraction of the substance and divide by one hundred percent: 365 * 20/100 = 73g.
2. Find the molar mass of hydrochloric acid: 1 + 35.5 = 36.5.
3) Find the amount of hydrochloric acid substance: 73 / 36.5 = 2 mol.
4) According to the reaction equation, there is one mole of carbon dioxide for two moles of hydrochloric acid. This means that the amount of carbon dioxide substance is: 2 * 2 = 4 mol.
5) Molar volume of gases: 22.4.
6) The volume of carbon dioxide: 4 * 22.4 = 89.6 liters – the answer.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.