How much CO2 will be released when burning 100 g of coal containing 20% impurities.
| March 2, 2021 | education
Combustion of coal with the release of carbon dioxide.
C + O2 = CO2.
Let’s determine the mass of impurities.
m (approx.) = 100 g • 20% / 100% = 20 g.
A mass of pure coal without impurities.
m (C) = 100 g – 20 g = 80 g.
The amount of moles of carbon and carbon dioxide will be equal.
n (C) = n (CO2) = m / Mr = 80 g / 12 g / mol = 6.6 mol.
V (CO2) = n (CO2) • Vm = 6.6 mol • 22.4 mol / L = 149.3 L.
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