How much CO2 will be released when burning 600 kg of butanol?
The oxidation reaction of butanol is described by the following chemical reaction equation.
C4H9OH + 6O2 = 4CO2 + 5H2O |;
According to the coefficients of this equation, 6 oxygen molecules are required to oxidize 1 butanol molecule. In this case, 4 molecules of carbon dioxide are synthesized.
Let’s calculate the amount of butanol available.
To do this, divide the weight of the available gas by the weight of 1 mole of this gas.
M C4H9OH = 12 x 4 + 10 + 16 = 74 grams / mol;
N C4H9OH = 600,000/74 = 8,108 mol;
The amount of carbon dioxide will be.
N CO2 = 8 108 x 4 = 32 432 mol;
Let’s calculate the gas volume. To do this, we multiply the amount of substance by the volume of 1 mole of gas.
Its volume will be: V CO2 = 32 432 x 22.4 = 726 477 liters = 726.5 m3;