How much copper do you need to take to get 16 g of copper oxide (ll)? How much oxygen is required for this reaction?

Metallic copper reacts with oxygen to form oxide. The reaction is described by the following chemical equation:

Cu + ½ O2 = CuO ↑;

Let’s calculate the chemical amount of copper oxide. For this purpose, we divide the mass of the available substance by the weight of 1 mole.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 16/80 = 0.2 mol;

To get this amount of copper oxide, you need to take the same amount of copper.

Find the weight of the copper. To do this, multiply the amount of the substance by the weight of 1 mole of the substance.

M Cu = 64 grams / mol;

m Cu = 0.2 x 64 = 12.8 grams;

To obtain such an amount of copper oxide, it is necessary to take 2 times less oxygen.

Let’s calculate the weight of oxygen.

To find the weight, we multiply the amount of the substance by the weight of 1 mole of the substance.

M O2 = 16 x 2 = 32 grams / mol;

m O2 = 0.2 / 2 x 32 = 3.2 grams;