How much copper is released at the cathode at a current of 2A in 25 minutes?

Initial data: I (current strength) = 2 A; t (duration of copper release at the cathode) = 25 min (1500 s).

Reference values: k (electrochemical equivalent of copper) = 32.9 * 10-8 kg / C.

The mass of copper released at the cathode is determined by the formula: m = k * I * t.

Let’s calculate: m = 32.9 * 10-8 * 2 * 1500 ≈ 0.001 kg (1 g).

Answer: 1 gram of copper will be released at the cathode.