How much could 1 kg of water be heated using the heat required to melt 1 kg of ice at 0 degrees?
| September 5, 2021 | education
Problem data: m1 (water mass) = 1 kg = m2 (ice mass); t0 (initial ice temperature) = 0 (corresponds to the ice melting temperature).
Reference values: Cw (specific heat capacity of water) = 4200 J / (kg * K); λ (specific heat of melting of ice) = 3.4 * 105 J / kg.
The change in temperature of 1 kg of water can be expressed from the equality: Cw * m1 * Δt = λ * m2 and Δt = λ * m2 / (Cw * m1) = λ / Cw.
Calculation: Δt = 3.4 * 105/4200 = 80.95 ºС.
Answer: The water could be heated to 80.95 ºС.
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