How much do you need to mix hot water with t = 90 and cold water t = 10 to get 100 kg of water with t = 30.

We are given: t1 = 90 C t2 = 10 C t = 30 C m = 100 kg
Find: m1, m2-?
Solution: c * m1 * (t1-t) = c * m2 * (t-t2) <=> m1 * (t1-t) = m2 * (t-t2) -> m1 / m2 = (t-t2) / (t1-t) = 1/3 -> m2> m1 3 times. Because m = m1 + m2 = 4m1 -> m1 = m / 4 = 100/4 = 25 (kg) -> m2 = m-m1 = 100-25 = 75 (kg)
Answer: m1 = 25 kg; m2 = 75 kg.



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