How much do you need to take 10% and 30% copper sulfate solution to get 200 g of 16% copper sulfate?

We compose a system of equations in which we write the mass of a 10% solution as x grams, and the weight of a 30% solution as 3.

In this case, their total weight will be:

x + y = 200 grams.

Find the mass of copper in the resulting solution.

200 * 16% / 100% = 2 * 16 = 32 grams.

We get the second equation for the sum of the weight of copper.

0.1 * x + 0.3 * y = 32.

Express the value of x from the first equation and substitute it into the second.

x = 200 – y.

0.1 * (200 – y) + 0.3 * y = 32.

20 – 0.1 * y + 0.3 * y = 32.

0.2 * y = 32 – 20.

0.2 * y = 12.

y = 12 / 0.2 = 60 g (30% solution).

x = 200 – 60 = 140 g (10% solution).

Answer: 140 and 60 grams.