# How much does the internal energy of 10 kg of ice, taken at a temperature

How much does the internal energy of 10 kg of ice, taken at a temperature of 0 degrees, increase as a result of its transformation into steam with a temperature of 100 degrees.

Ice at a temperature of 0 degrees will immediately begin to melt, water is formed.

Then the water will be heated up to 100 degrees. And after that it will start to evaporate. In all three processes, the energy of the body will increase.

The total energy is calculated by the formula:

Q = Q1 + Q2 + Q3.

Q1 = L * m (for melting),

Q2 = c * m * (t2 – t1) (for heating)

Q3 = λ * m (for vaporization)

L, с, λ – we find from the tables:

L = 3.4 * 10 ^ 5 J / kg, s = 4200 J / (kg * ºС), λ = 2.3 * 10 ^ 6 J / kg.

Let’s calculate the energy:

Q = (3.4 * 10 ^ 5 J / kg * 10 kg) + (4200 J / (kg * ºС) * 10 kg * (100 ºС – 0 ºС)) + (2.3 * 10 ^ 6 J / kg * 10 kg) = 34 * 10 ^ 5 + 42 * 10 ^ 5 + 230 * 10 ^ 5 = 306 10 ^ 5 J = 30.6 10 ^ 6 J

Answer: Q = 30.6 10 ^ 6 J.

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