How much energy does it take to completely evaporate 60 grams of mercury at 357 degrees Celsius.

Initial data: m (mass of mercury for evaporation) = 60 g; t (initial temperature of mercury, boiling point of mercury) = 357 ºС.

Reference data: L (specific heat of vaporization of mercury) = 3 * 10 ^ 5 J / kg

SI system: m = 60 g = 60/1000 kg = 0.06 kg.

The required amount of energy for the complete evaporation of mercury is determined by the formula: Q = L * m.

Let’s do the calculation:

Q = 3 * 10 ^ 5 * 0.06 = 18,000 J or 18 kJ.

Answer: For complete evaporation of 60 g of mercury, 18 kJ of energy is required.