How much energy is released during the decay of all uranium atoms m = 90 g, if the mass of 1 atom is 3.9 * 10 ^ – 25

How much energy is released during the decay of all uranium atoms m = 90 g, if the mass of 1 atom is 3.9 * 10 ^ – 25. When one atom is fission, 200 MeV of energy is released …

Uranium atoms decay gradually, releasing energy. From the condition of the problem it is known that a metal body is taken containing m = 90 g = 0.09 kg of uranium. Knowing that the mass of one atom is mo = 3.9 ∙ 10 ^ (- 25) kg, you can find the number of uranium atoms N in it by the formula N = m: mo. Fission of one atom releases Wо = 200 MeV energy. Then all atoms during decay will release N times more energy W = Wо ∙ N, we get W = Wо ∙ m: mo. Substitute the values ​​of physical quantities in the calculation formula and make calculations: W = 200 ∙ 0.09: (3.9 ∙ 10 ^ (- 25)) = 4.61 ∙ 10 ^ (25) (MeV).
Answer: 4.61 ∙ 10 ^ (25) MeV energy is released during the decay of all uranium atoms.



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