How much energy is required to completely evaporate 200 g of ether taken at a temperature of 20

How much energy is required to completely evaporate 200 g of ether taken at a temperature of 20 degrees C at the boiling point?

Data: m (mass of ether for evaporation) = 200 g = 0.02 kg; tн (ether temperature) = 20 ºС.

Reference data: C (specific heat of ether) = 2350 J / (K * kg)); L (specific heat of vaporization of ether) = 4 * 10 ^ 5 J / kg; t (temperature of vaporization of ether) = 35 ° С.

SI system: m = 200 g = 0.2 kg.

The amount of energy for heating and vaporization: Q = m * (C * (t – tн) + L).

Q = 0.2 * (2350 * (35 – 20) + 4 * 10 ^ 5) = 87,050 J.

Answer: For heating and vaporization of the ether, 87,050 J.



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