How much energy is required to obtain 100 degree steam from ice weighing 2 kg, which has a temperature of -10 degrees.

univerkov | November 20, 2020 | education

Q = Q1 + Q2 + Q3 + Q4.
Q = C1 * m * (tк1 – tн1), С1 – beats. heat capacity. ice (C1 = 2100 J / (kg * K)), m – mass (m = 2 kg), tк1 = 0 ºС, tн1 = -10 ºС.
Q2 = λ * m, λ – beats. heat of fusion (λ = 34 * 104 J / kg).
Q3 = C2 * m * (tк2 – tн2), C2 – beats. heat capacity. water (С2 = 4200 J / (K * kg)), tк2 = 100 ºС, tн2 = 0 ºС.
Q4 = L * m, L – beats. heat steam (L = 2.3 * 106 J / kg).
Q = 2100 * 2 * (0 – (-10)) + (34 * 104) * 2 + 4200 * 2 * (100 – 0) + 2.3 * 106 * 2 = 6162000 J = 6.162 MJ.

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