How much energy is required to turn 150g water into steam at 100 degrees Celsius?

The amount of energy Q required to evaporate 150 g of water:
Q = Lm, where L is the specific heat of vaporization of water at atmospheric pressure, m is the mass of water.
Q = 2258 kJ / kg * 0.15 kg = 338.7 kJ.
Answer: 338.7 kJ



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