How much energy is required to turn water weighing 150 g into steam at a temperature of 100C.

As we can see from the problem statement, the temperature is 100 degrees. That is the boiling point of water.

Let us find out how much energy will be needed in order to turn 150 grams of water into steam, when we know that the specific heat of vaporization of water is 2260 kJ:

150 grams = 150: 1000 = 0.15 kilograms;

2260 kJ = 2260000 J;

Q = 0.15 * 2260000 = 339000.

Answer: Under these initial conditions, in order to turn 150 grams of water into steam, 339,000 Joules of energy (or 339 kJ) are required.