How much energy needs to be spent to bring water with a mass of 5 kg

How much energy needs to be spent to bring water with a mass of 5 kg, taken at a temperature of 0 degrees Celsius, to a boil and evaporate it?

The amount of energy that needs to be spent to heat and evaporate 5 kg of water:
Q = cm (t2 – t1) + Lm, where c is the specific heat capacity of water, t2 – t1 is the difference between the final and initial temperatures during heating.
Q = 4,200 kJ / (kg deg) * 5 kg * 100 ° C + 2258 kJ / kg * 5 kg = 13 390 kJ.
Answer: 13 390 kJ (13.4 MJ).