How much energy was spent on heating an iron rivet with a mass of 140 g from 20 to 920?

univerkov | November 29, 2020 | education

Given: m = 140g = 0.14 kg; t2 = 920 ° C, t1 = 20 ° C
Find: Q
Solution: Q = cm (t2-t1), c- specific heat of iron, c = 460 J / kg • ° C, Q = 460 • 0.14 • 900 = 57960 J
Answer: 57960 J

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